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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The nthn^{\text {th}} term of series 11+1+22+1+2+33+…\frac{1}{1}+\frac{1+2}{2}+\frac{1+2+3}{3}+\ldots will be
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Correct option: A
n+12\frac{n+1}{2}
Option A (n+12\frac{n+1}{2}) is correct because the nth term is the sum of the first n integers divided by n, which simplifies to (n+1)/2.

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