JEE PHYSICS MCQ: WAVES

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Application +4 | -1

Two whistles A and B have frequencies

600 \mathrm{~Hz}

and

590 \mathrm{~Hz}

reactively. An observer is standing in the middle of the line joining the two sources. Source

B

and observer are moving towards right with velocity

30 \mathrm{~m} / \mathrm{s}

and

\mathrm{A}

is standing at left side. If the velocity of sound in air is

300 \mathrm{~m} / \mathrm{s}

, the number of beats listened by the observer are:

View answer and explanation

Correct option: B

Option B (4) is correct because the beat frequency is the difference between the frequencies heard by the observer from the two whistles.

More Questions from WAVES

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3\,\,kHz

0.5

f\mathrm{ }Hz

V\mathrm{ }m/sec

0.2\,\,V

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

(– \mathrm{ve}) \,x

y = f(kx +\omega t),

X

0.01\,\,s

5 \mathrm{~m}

245 \mathrm{~g}

1 \mathrm{~kg}

g=980 \mathrm{~cm} \mathrm{~s}^{-2}

T

V