JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

The sum of all possible products of the first

n

natural mumbers taken two by two, is

View answer and explanation

Correct option: A

\frac{1}{24} n(n+1)(n-1)(3 n+2)

Option A (

\frac{1}{24} n(n+1)(n-1)(3 n+2)

) is correct because it is the sum of all possible products of the first n natural numbers taken two by two.

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

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{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

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\log \left(\frac{a}{3 b}\right)

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\frac{3}{4}