JEE PHYSICS MCQ: WAVE OPTICS

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Analyzing +4 | -1

Statement-1 : When light is incident from air to water then Brewster's angle is

\theta_{{B}}

then if light is incident from water to air then Brewster's angle is

\frac{\pi}{2}-\theta_{{B}}

.
Statement-2 : When light goes from air to any medium of refractive index is then Brewster's angle

\left(\theta_{{B}}\right)

is given by

\theta_{{B}}=\tan ^{-1}(\mu)

View answer and explanation

Correct option: A

Both statement-1 and Statement-2 is true

Both statement-1 and Statement-2 are true. Statement 2 is the definition of Brewster's angle, and statement 1 correctly relates Brewster's angles for air-water and water-air interfaces.

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