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NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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The correct sequence of decreasing number of π\pi–bonds in the structures of H2SO3,H2SO4   and  H2S2O7{H_2}S{O_3},{H_2}S{O_4}\,\,\,and\,\,{H_2}{S_2}{O_7} is
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Correct option: C
  H2S2O7>H2SO4>H2SO3\,\,{H_2}{S_2}{O_7} > {H_2}S{O_4} > {H_2}S{O_3}
Option C (H2S2O7>H2SO4>H2SO3\mathrm{H}_2\mathrm{S}_2\mathrm{O}_7 > \mathrm{H}_2\mathrm{S}\mathrm{O}_4 > \mathrm{H}_2\mathrm{S}\mathrm{O}_3) is correct because H2S2O7{H_2}{S_2}{O_7} has the most pi bonds, followed by H2SO4{H_2}S{O_4}, and then H2SO3{H_2}S{O_3}.

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