JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

\lim \limits_{{h \rightarrow 0}} \frac{\sqrt{x+h}-\sqrt{x}}{h}=

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Correct option: A

\frac{1}{2 \sqrt{x}}

Option A (

\frac{1}{2 \sqrt{x}}

) is correct because the limit represents the derivative of

\sqrt{x}

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\lim \limits_{{x \rightarrow 0}}\left(\frac{1}{x^2}-\operatorname{cosec}^2 x\right)

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\lim \limits_{{x \rightarrow \infty}} x\left(e^{1 / x}-1\right)

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f^{\prime}(0)

\lim\limits_{n \to \infty } {\left( {1 + \sin \frac{a}{n}} \right)^n}