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JEE MATHEMATICS MCQ: PERMUTATIONS

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The value of ∑r=1n   nPrr!\sum \limits_{r = 1}^n \,\frac{{{\;^n}{P_r}}}{{r!}} is
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Correct option: B
2n−1{2^n} - 1
Option B (2n−1{2^n} - 1) is correct because the given summation is equivalent to the binomial expansion of (1+1)n(1+1)^n excluding the first term.

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