JEE MATHEMATICS MCQ: PROBABILITY

1 Easy

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Application +4 | -1

A doctor is called to see a sick child. The doctor knows (prior to the visit) that

90 \%

of the sick children in that neighbourhood are sick with the flue, denoted by

F

, while

10 \%

are sick with the measles, denoted by M. A well-known symptom of measles is a rash, denoted by

R

.
The probability of having a rash for a child sick with the measles is

0.95

. However, occasionally children with the flue also develop a rash with conditional probability

0.08

. Upon examination the child, the doctor finds a rash, then the probability that the child has the measles, is

View answer and explanation

Correct option: D

\frac{95}{167}

Option D (

\frac{95}{167}

) is correct because it is calculated using Bayes' theorem to find the probability of measles given a rash.

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\begin{array}{cccccc}X: & 1 & 2 & 3 & 4 & 5 \\ P(X): & k^2 & 2 k & k & 2 k & 5 k^2\end{array}

P(X>2)

\left( {2\;n + 1} \right)

n

n + 1

n

A

B

P\left( {A \cap B'} \right) = \frac{3}{{25}}

P\left( {A' \cap B} \right) = \frac{8}{{25}}

P\left( A \right)

A

B

A

B

B

A