JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

\cos \theta \cos 2 \theta \cos 4 \theta \ldots \cos 2^{n-1} \theta

is equal to

View answer and explanation

Correct option: A

\frac{\sin 2^n \theta}{2^n \sin \theta}

Option A is correct because the given expression can be simplified to

\frac{{\sin 2^n \theta}}{{2^n \sin \theta}}

using trigonometric identities.

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