NEET UG PHYSICS MCQ: GRAVITATION

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Analyzing +4 | -1

In the following four periods
(i) Time of revolution of a satellite just above the earth’s surface

\left( {{T_{st}}} \right)

, (ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth

\left( {{T_{ma}}} \right)

, (iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of

9.8N/kg\left( {{T_{sp}}} \right)

, (iv) Period of an infinite length simple pendulum in the earth’s real gravitational filed

\left( {{T_{is}}} \right)

View answer and explanation

Correct option: C

{T_{sp}} > {T_{is}}

Option C (

{T_{sp}} > {T_{is}}

) is correct because the period of a simple pendulum with length equal to Earth's radius in a uniform field is greater than that of an infinite length pendulum in Earth's real field.

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.