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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
If a,b,ca, b, c are in AP and ∣a∣,∣b∣,∣c∣<1|a|,|b|,|c|<1 and x=1+a+a2+…+∞x=1+a+a^2+\ldots+\infty, y=1+b+b2+…+∞y=1+b+b^2+\ldots+\infty, z=1+c+c2+…+∞z=1+c+c^2+\ldots+\infty
Then, x,y,zx, y, z will be in
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Correct option: C
HP
Option C (HP) is correct because if a, b, c are in AP, then 1-a, 1-b, 1-c are also in AP. Since x, y, z are the reciprocals of these terms, they are in HP.

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