Every atom makes one free electron in copper. If ${\rm{1}}{\rm{.1 }}\,{\rm{A}}$ Current is flowing in the wire of copper having ${\rm{1 mm}}$ diameter, then the drift velocity(approx.) will be (density of copper = $9\,\, \times \,\,{10^3}\,\,{\rm{k}}\,{\rm{g}}{{\rm{m}}^{ - 3}}$ and atomic weight of copper =${\rm{63}}$)

$0.1\,\,{\rm{mm}}{{\rm{s}}^{ - 1}}$

$0.2\,\,{\rm{mm}}{{\rm{s}}^{ - 1}}$

$0.3\,\,{\rm{mm}}{{\rm{s}}^{ - 1}}$

$0.2\,\,{\rm{mm}}{{\rm{s}}^{ - 1}}$

JEE PHYSICS MCQ: CURRENT ELECTRICITY

1 Medium

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Application +4 | -1

Every atom makes one free electron in copper. If

\mathrm{1}\mathrm{.1 }\,\mathrm{A}

Current is flowing in the wire of copper having

\mathrm{1 mm}

diameter, then the drift velocity(approx.) will be (density of copper =

9\,\, \times \,\,{10^3}\,\,\mathrm{k}\,\mathrm{g}{\mathrm{m}^{ - 3}}

and atomic weight of copper =

\mathrm{63}

)

View answer and explanation

Correct option: A

0.1\,\,\mathrm{mm}{\mathrm{s}^{ - 1}}

Option A (

0.1\\,\\,\mathrm{mm}{\mathrm{s}^{ - 1}}

) is correct because the drift velocity is calculated using the formula relating current, number density of electrons, area, and charge.