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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
Let a1,a2,a3,…a_{1}, a_{2}, a_{3}, \ldots be aa G. P. such that a1<0,a1+a2=4a_{1}<0, a_{1}+a_{2}=4 and a3+a4=16a_{3}+a_{4}=16. If ∑i=19ai=4λ\sum_{\mathrm{i}=1}^{9} a_{i}=4 \lambda, then λ\lambda is equal to:
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Correct option: B
-171
Option B (-171) is correct because it is the value of lambda calculated by finding the first term and common ratio of the G.P. and then using the sum formula.

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