The value of 'n' in the reaction ${\rm{C}}{{\rm{r}}_2}{\rm{O}}_7^{2 - } + 14{{\rm{H}}^ + } + n{\rm{F}}{{\rm{e}}^{2 + }} \to 2{\rm{C}}{{\rm{r}}^{3 + }} + n{\rm{F}}{{\rm{e}}^{3 + }} + 7{{\rm{H}}^2}{\rm{O}}$ will be

JEE CHEMISTRY MCQ: REDOX REACTIONS

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The value of 'n' in the reaction

\mathrm{C}{\mathrm{r}_2}\mathrm{O}_7^{2 - } + 14{\mathrm{H}^ + } + n\mathrm{F}{\mathrm{e}^{2 + }} \to 2\mathrm{C}{\mathrm{r}^{3 + }} + n\mathrm{F}{\mathrm{e}^{3 + }} + 7{\mathrm{H}^2}\mathrm{O}

will be

View answer and explanation

Correct option: C

Option C (6) is correct because the value of 'n' is determined by balancing the redox reaction, specifically the number of electrons transferred during the oxidation and reduction processes.

More Questions from REDOX REACTIONS

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The oxidation number of

\mathrm{H}

in sodium hydride is A reagent, which can decrease the oxidation number of an element, is called Consider the following decomposition reaction

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

In the above reaction, Assertion (A):

\mathrm{HNO}_3

acts as oxidizing agent.

Reason (R): Oxidation no. of nitrogen is +5, no increase in oxidation no. beyond +5 can occur. The oxidation no. of

\mathrm{HNO}_3

can only decrease. Assertion :- Bromide ion is serving as a reducing agent in the reaction.

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

Reason :- Oxidation number of

\mathrm{Br}

increases from

-1

+5.

A substance, that by its sharp colour change indicates the completion of reaction is known as :