NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Hard

1 of 1

Analyzing +4 | -1

When photons of energy

4.25 \mathrm{~eV}

strike the surface of a metal

{A}

, the ejected photoelectrons have maximum kinetic energy,

{T}_{{A}}

(expressed in

\mathrm{eV}

) and de-Broglie wavelength

\lambda_{{A}}

. The maximum kinetic energy of photo electrons liberated from another metal

{B}

by photons of energy

4.20 \mathrm{~eV}

T_B=\left(T_A-1.50\right) \mathrm{eV}

. If the de-Broglie wavelength of these photo electrons is

\lambda_{{B}}=2 \lambda_{{A}}

, then

View answer and explanation

Correct option: C

{T}_{{A}}=2.00 \mathrm{~eV}

Option C (

{T}_{{A}}=2.00 \mathrm{~eV}

) is correct because by using the de-Broglie wavelength relationship and the photoelectric effect equation, we can solve for the kinetic energy of the ejected photoelectrons from metal A.

More Questions from STRUCTURE OF ATOM

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Which of the following pairs have identical values of e/m? The correct de Broglie relationship is: Assertion: Unlike sound waves, electromagnetic waves do not require medium and can move in vacuum.

Reason: The oscillating electric and magnetic fields produced by oscillating charged particles are parallel to each other and both are perpendicular to the direction of propagation of the wave. S-I: The

{p}_{{x}}

orbital has maximum electron density along the y axis and its nodal plane is xz plane.

S-II : For a given atom, for all values of

n

, the

{p}

-orbitals have the same shape, but the overall size decreases as '

n

' increases. S-I: Elements like

Rb, Cs, Tl, In, Ga

and

Sc

were discovered when their minerals were analysed by spectroscopic methods.

S-II: The element helium was discovered in the sun by spectroscopic method. In which one of the following, the number of protons is greater than number of neutrons but number of protons is less than the number of electrons?