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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
The solution set of 2x−13≥(3x−24)−(2−x5)\frac{2 x-1}{3} \geq\left(\frac{3 x-2}{4}\right)-\left(\frac{2-x}{5}\right) is (−∞,a](-\infty, a]. The value of 'aa' is
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Correct option: A
2
Option A (2) is correct because solving the inequality 2x−13≥3x−24−2−x5\frac{2x-1}{3} \geq \frac{3x-2}{4} - \frac{2-x}{5} results in x≤2x \leq 2, which corresponds to the interval (−∞,2](-\infty, 2].

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