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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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50W/m250\mathrm{ W/}{\mathrm{m}^2} energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1m2\mathrm{1 }{\mathrm{m}^\mathrm{2}} surface area will be close to (c=3×108  m/s)(c = 3 \times {10^8}{\rm\,\,{m/s)}}
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Correct option: A
20×10−8N20 \times {10^{ - 8}}\mathrm{N}
Option A (20×10−8N20 \times {10^{ - 8}}\mathrm{N}) is correct because it calculates the force exerted by the sunlight considering both the absorbed and reflected portions of the incident energy.

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