JEE CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

1 Medium

1 of 1

Understanding +4 | -1

In the following

\underset{(p)}{\left[{Al}\left({H}_2 {O}\right)_6\right]^{3+}}+\underset{(q)}{{HCO}_3^{-}} \Leftrightarrow \underset{(r)}{\left[{Al}\left({H}_2 {O}\right)_5 {OH}\right]^{2+}}+\underset{(s)}{{H}_2 {CO}_3}

species behaving as Brosnted-Lowry acids are

View answer and explanation

Correct option: A

(p), (s)

Option A (

(p), (s)

) is correct because in the forward reaction,

[{Al}({H}_2 {O})_6]^{3+}

donates a proton, and in the reverse reaction,

{H}_2 {CO}_3

donates a proton, thus acting as Bronsted-Lowry acids.

More Questions from 13 TH GROUP ELEMENTS (P-BLOCK)

Practice All Chapter MCQs →

{AlCl}_3

{Al}_2 {Cl}_6

\left[M\left({H}_2 {O}\right)_6\right]^{3+}

{Cl}^{-}

{Al}_2\left({SO}_4\right)_3

{Tl}>{In}>{Ga}>{Al}>{B}

{Al}

{HCl}

{H}_2

{HNO}_3

{Al}

{Al}

\left[{Al}\left({H}_2{O}\right)_6\right]^{3+}

\mathrm{sp}^3 \mathrm{d}^2