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JEE CHEMISTRY MCQ: STATES OF MATTER

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Application +4 | -1
For a Vander Waal's gas the volume of gas molecules are negligible. The molar volume of gas is 20 L/mol20 \mathrm{~L} / \mathrm{mol} at 300 K300 \mathrm{~K}. The compressibility factor of the gas is

[Given: a=96 L2⋅atm⋅mol−2{a}=96 \mathrm{~L}^2 \cdot \mathrm{atm} \cdot \mathrm{mol}^{-2} and R=0.08 L⋅atm⋅mol−1 K−1{R}=0.08 \mathrm{~L} \cdot \mathrm{atm} \cdot \mathrm{mol}^{-1} \mathrm{~K}^{-1}]
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Correct option: A
0.8
Option A (0.8) is correct because the compressibility factor is calculated using the van der Waals equation, considering the given parameters.

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