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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
1 of 1
Application +4 | -1
Let f:R→Rf: R \rightarrow R be defined as f(x)=ae2x+bex+cxf(x)=a e^{2 x}+b e^x+c x. If f(0)=−1,f′(log⁡e2)=21f(0)=-1, f^{\prime}\left(\log _e 2\right)=21 and ∫0log⁡e4(f(x)−cx)dx=392\int\limits_{0}^{\log _e 4}(f(x)-c x) d x=\frac{39}{2}, then the value of ∣a+b+c∣|a+b+c| equals
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Correct option: D
8
Option D (8) is correct because it involves solving a system of equations derived from the given conditions on the function f(x) and its derivative.

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