NEET UG PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1

Let

P\left( r \right) = \frac{Q}{{\pi {R^4}}}r

be the charge density distribution for a solid sphere of radius

R

and total charge

Q.

. For a point

'p'

inside the sphere at distance

{r_1}

from the centre of the sphere, the magnitude of electric field is

View answer and explanation

Correct option: C

\frac{{Qr_1^2}}{{4\pi { \in _0}{R^4}}}

Option C is correct because the electric field inside the sphere is calculated using Gauss's law, considering the charge enclosed within the radius r1.

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The ratio of magnitude of electric displacement (D) and electric field (E) is Gauss’s Law is valid for In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of: Statement-1:

\overrightarrow{{E}}

in outside velocity of a conductor depends only on the local charge density

\alpha

.
Statement-2:

\overrightarrow{{E}}

in outside vicinity of a conductor is given by

\frac{\sigma}{\varepsilon_0}

. Two charges each of 1 coulomb are at a distance 1

km

apart the force between them is

P \times 10^3

then value of

{P}

is Electric field due to point charge depends on distance

r