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JEE PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1

The equation of two light waves are

\begin{aligned} & y_1=A_1 \sin 2 \omega t \\ & y_2=A_2 \cos \left(2 \omega t+\frac{\pi}{6}\right) \end{aligned}

What will be the value of phase difference at time

t

View answer and explanation

Correct option: B

\frac{2 \pi}{3}

Option B (

\frac{{2 \pi}}{{3}}

) is correct because the phase difference is calculated by converting cosine to sine and then finding the difference in phase angles.

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