Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Medium
1 of 1
Application +4 | -1
If the AM is twice the GM of the numbers aa and bb, then a:ba: b will be
View answer and explanation
Correct option: B
2+32−3\frac{2+\sqrt{3}}{2-\sqrt{3}}
Option B (2+32−3\frac{2+\sqrt{3}}{2-\sqrt{3}}) is correct because solving the given condition AM = 2GM leads to the ratio a:b=(2+3):(2−3)a:b = (2+\sqrt{3}):(2-\sqrt{3}).

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.