JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

1 of 1

Application +4 | -1

All ellipse has its centre at

\left( {1, - 1} \right)

and semi-major axis

= 8

and it passes through the point

\left( {1,3} \right)

. The equation of the ellipse is

View answer and explanation

Correct option: B

\frac{{{{\left( {x - 1} \right)}^2}}}{{64}} + \frac{{{{\left( {y + 1} \right)}^2}}}{{16}} = 1

Option B (

\frac{{{{\left( {x - 1} \right)}^2}}}{{64}} + \frac{{{{\left( {y + 1} \right)}^2}}}{{16}} = 1

) is correct because it satisfies the given conditions: center at (1, -1), semi-major axis of 8, and passing through the point (1, 3).

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

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P

9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

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r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O