JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

The wave function (

\Psi

) of 2 s is given by

\Psi_{2 s}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{r}{a_0}\right) e^{-f / 2 a_0}

r=r_0

, radial node is formed. Thus,

r_0

in terms of

a_o

View answer and explanation

Correct option: A

r_0=2 a_0

Option A (

r_0=2 a_0

) is correct because at the radial node, the wave function

\Psi_{2s}

is equal to zero.

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