JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

The value of positive real parameter a such that the area of region bounded by parabolas

y=x-

a x^2, a y=\mathrm{x}^2

attains its maximum value is equal to

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Correct option: D

Option D (1) is correct because the area is maximized when a = 1, which can be found by differentiating the area with respect to 'a' and setting it to zero.

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[*]

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\int\limits_{{-2}}^0\left(x^3+3 x^2+3 x+3+(x+1) \cos (x+1)\right) d x

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