JEE MATHEMATICS MCQ: DCS AND DRS

1 Easy

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Application +4 | -1

The angle between the lines whose direction cosines satisfy the equations

l+m+n=0

and

l^2=m^2+n^2

View answer and explanation

Correct option: C

\frac{\pi}{3}

Option C (

\frac{\pi}{3}

) is correct because it is the angle between the two lines whose direction cosines satisfy the given equations, found by solving for the direction cosines and using the dot product formula.

More Questions from DCS AND DRS

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If the line

\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z

makes a right angle with the line

\frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7},

then

4 \lambda+9 \mu

is equal to: The shortest distance between the lines

\frac{x}{2}=\frac{y}{2}=\frac{z}{1}

and

\frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}

lies in the interval :
A uniform rod,

4 {~m}

in length and weight

2 {~kg}

turns freely about a point distant one metre from one end and from that end a weight of

10 {~kg}

is suspended. The weight that must be placed at the other end to produce equilibrium is A line makes angles of

45^{\circ}

and

60^{\circ}

with the positive axes of

X

and

Y

respectively. The angle made by the same line with the positive axis of

Z

, is. The direction cosines of a line segment

\mathrm{AB}

are

-2 / \sqrt{17}

3 / \sqrt{17},-2 / \sqrt{17}

\mathrm{AB}=\sqrt{17}

and the co-ordinates of

\mathrm{A}

are

(3,-6,10)

then the co-ordinates of

\mathrm{B}

are
A line

A B

in three-dimensional space makes angles

45^{\circ}

and

120^{\circ}

with the positive

X

-axis and the positive

Y

-axis, respectively. If

A B

makes an acute angle

\theta

with the positive

Z

-axis, then

\theta

equals