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JEE PHYSICS MCQ: OSCILLATIONS

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A particle starts S.H.M. from the mean position. Its amplitude is a and total energy E{E}. At one instant 5 its kinetic energy is 3 E/43 {~E} / 4, its displacement at this instant is
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Correct option: B
y=a2y=\frac{a}{2}
Option B (y=a2y=\frac{a}{2}) is correct because it represents the displacement at the given kinetic energy, calculated using the energy conservation principle in SHM.

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