If $A + C = 2B$, then $\frac{{\cos \,\,C - \cos \,\,A}}{{\sin \,\,A - \sin \,\,C}}$ is equal to

JEE MATHEMATICS MCQ: TRANSFORMATIONS

1 Easy

1 of 1

Application +4 | -1

A + C = 2B

, then

\frac{{\cos \,\,C - \cos \,\,A}}{{\sin \,\,A - \sin \,\,C}}

is equal to

View answer and explanation

Correct option: D

\tan \,\,B

Option D (

\tan \,B

) is correct because by using the sum-to-product formulas and the given condition

A + C = 2B

, the expression simplifies to

\tan \,B

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