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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1
If sin⁡  6θ=32  cos⁡5  θ  sin⁡  θ−32  cos⁡3θ  sin⁡  θ+3x\sin \,\,6\theta = 32\,\,{\cos ^5}\,\,\theta \,\,\sin \,\,\theta - 32\,\,{\cos ^3}\theta \,\,\sin \,\,\theta + 3x, then xx is equal to
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Correct option: D
sin⁡  2θ\sin \,\,2\theta
Option D (sin⁡ 2θ\sin \,2\theta) is correct because by using the triple angle formula for sine and simplifying, we find that x=sin⁡ 2θx = \sin \,2\theta.

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