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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
If ∣cos⁡−11n∣<π2\left|\cos ^{-1} \frac{1}{n}\right| < \frac{\pi}{2}, then lim⁡n→∞{(n+1)2πcos⁡−11n−n}\lim \limits_{{n \rightarrow \infty}}\left\{(n+1) \frac{2}{\pi} \cos ^{-1} \frac{1}{n}-n\right\} is equal to
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Correct option: B
π−2π\frac{\pi-2}{\pi}
Option B (π−2π\frac{\pi-2}{\pi}) is correct because after applying trigonometric identities and evaluating the limit, the expression simplifies to π−2π\frac{\pi-2}{\pi}.

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