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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If log⁡102=0.3010…\log _{10} 2=0.3010 \ldots, the number of digits in the number 200020002000^{2000} is
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Correct option: C
6603
Option C (6603) is correct because the number of digits in 200020002000^{2000} is found by calculating log⁡10(20002000)\log_{10}(2000^{2000}) and adding 1 to the integer part of the result.

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