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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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A body of mass m starts moving from rest along x-axis so that its velocity varies as

v = a\sqrt s

where a is a constant and s is the distance covered by the body. The total work done by all the forces acting on the body in the first t second after the start of the motion is:

View answer and explanation

Correct option: A

\frac{1}{8}m{a^4}{t^2}

Option A (

\frac{1}{8}m{a^4}{t^2}

) is correct because it is derived from calculating the work done using the work-energy theorem, considering the velocity's dependence on distance and time.

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