$\mathop \smallint \nolimits_{ - 100}^{100} \,\,f\,\,\left( x \right)\,\,dx$ is equal to

$\mathop \smallint \nolimits_{ - 100}^{100} \,\,f\left( { - x} \right)\,\,dx$

$\mathop \smallint \nolimits_{ - 100}^{100} \,\,f\left( {{x^2}} \right)\,\,dx$

$\mathop \smallint \nolimits_{ - 100}^{100} \,\,f\left( { - \,{x^2}} \right)\,\,dx$

$\mathop \smallint \nolimits_{ - 100}^{100} \,\,f\left( {\frac{1}{x}} \right)\,\,dx$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Understanding +4 | -1

\int \nolimits_{ - 100}^{100} \,\,f\,\,\left( x \right)\,\,dx

is equal to

View answer and explanation

Correct option: D

\int \nolimits_{ - 100}^{100} \,\,f\left( { - x} \right)\,\,dx

Option D (

\int \nolimits_{ - 100}^{100} \,f\left( { - x} \right)\,dx

) is correct because substituting

x = -t

results in the same integral.

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