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JEE MATHEMATICS MCQ: RATE MEASURE

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Application +4 | -1

the speed v of particle moving along a straight line is given by

a + {y^2} = {x^2}

(where

x

is its distance from the origin).The acceleration of the particle is

View answer and explanation

Correct option: C

\frac{x}{b}

Option B ((

- \infty ,\;0

)) is correct because the function is increasing when its derivative is positive, which occurs for x < 0.

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