JEE PHYSICS MCQ: MOTION IN PLANE

1 Hard

1 of 1

Application +4 | -1

If the unit vectors

\mathbf{e}_1

and

\mathbf{e}_2

are inclined at an angle

2 \theta

and

\left|\mathbf{e}_1-\mathbf{e}_2\right|<1

, then for

\theta \in[0, \pi], \theta

may lie in the interval

View answer and explanation

Correct option: A

\left[0, \frac{\pi}{6}\right)

Option A ([0,

\frac{\pi}{6}

)) is correct because it satisfies the inequality derived from the given condition |

\mathbf{e}_1 - \mathbf{e}_2

| < 1.

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}