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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
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Application +4 | -1
Let aΛ‰,bΛ‰,cΛ‰\bar{a}, \bar{b}, \bar{c} be three unit vectors such that aΛ‰\bar{a} is perpendicular to the plane of bΛ‰\bar{b} and cΛ‰\bar{c}. If the angle between bΛ‰\bar{b} and cΛ‰\bar{c} is Ο€/3\pi / 3 then ∣aΛ‰Γ—bΛ‰βˆ’aΛ‰Γ—cΛ‰βˆ£2|\bar{a} \times \bar{b}-\bar{a} \times \bar{c}|^2 is equal to
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Correct option: A
1
Option A (1) is correct because the magnitude squared of the cross product simplifies to 1 using the given conditions.

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