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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
lim⁡x→∞x2+1−x3+13x4+14−x4+15\lim\limits_{x \to \infty } \frac{{\sqrt {{x^2} + 1} - \sqrt[3]{{{x^3} + 1}}}}{{\sqrt[4]{{{x^4} + 1}} - \sqrt[5]{{{x^4} + 1}}}} equals
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Correct option: B
0
Option B (0) is correct because by dividing the numerator and denominator by the highest power of x and simplifying, the limit evaluates to 0.

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