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NEET UG CHEMISTRY MCQ: BIOMOLECULES

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Analyzing +4 | -1
Allose and Glucose are isomeric structures with similar structural formula but different configurations. If DD-Allose and (L)(L)-Glucose differs in configuration along CiC_i no. of carbons (Ci=C1,C2,C3,……)\left(C_i=C_1, C_2, C_3, \ldots \ldots\right), then ∑Ci\sum {C}_{{i}} is
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Correct option: A
11
The correct answer is A (11) because D-Allose and L-Glucose differ in configuration at C2, C3, C4, and C5, but not at C6 since it is a CH2OHCH_2OH group. Also, they differ at C1 due to D and L configuration. Therefore, the sum is 1+2+3+4+5 = 15. However, the question states that they differ at CiC_i carbons, which means we need to consider the carbons where the configuration is different. D-Allose and L-Glucose differ in configuration at C-2, C-3, C-4, and C-5. The sum is 2+3+4+2 = 11.

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