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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A lift in which a man is standing, is moving upward with a speed of 10ms−1.\mathrm{m}{\mathrm{s}^{ - 1}}.. The man drops a coin from a height of 4.9m and if g=9.8 ms−2\mathrm{m}{\mathrm{s}^{ - 2}}, then the coin reaches the floor of the lift after a time
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Correct option: B
1 s
Option B (1 s) is correct because the coin's time to reach the floor is determined by its relative motion with respect to the lift, which simplifies to free fall.

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