JEE PHYSICS MCQ: NUCLEI

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The binding energy of deuteron is 2.2 Mev and that of

{}_2H{e^4}

is 28 Mev. If two deuterons are fused to form one

{}_2H{e^4}

then energy released is

View answer and explanation

Correct option: C

23.6 Mev

Option C (23.6 Mev) is correct because the energy released is the difference between the binding energy of the Helium nucleus and twice the binding energy of the deuteron.

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