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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum to nn terms of the series 11.3+13.5+15.7+…\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\ldots, is
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Correct option: C
n2n+1\frac{n}{2 n+1}
Option C (n2n+1\frac{{n}}{{2n+1}}) is correct because the series can be expressed as a telescoping series, where most terms cancel out, leaving a simple expression in terms of nn.

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