JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum of

{\left( {x + 2} \right)^{n - 1}} + {\left( {x + 2} \right)^{n - 2}}\left( {x + 1} \right) + {\left( {x + 2} \right)^{n - 3}}{\left( {x + 1} \right)^2} + ... + {\left( {x + 1} \right)^{n - 1}}

is equal to

View answer and explanation

Correct option: C

{\left( {x + 2} \right)^n} - {\left( {x + 1} \right)^n}

Option C (

{\left( {x + 2} \right)^n} - {\left( {x + 1} \right)^n}

) is correct because the given expression is a geometric progression.

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