Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Medium
1 of 1
Analyzing +4 | -1
The sum of

12⋅2213+22.3213+23+32.4213+23+33+...\frac{{\frac{1}{2} \cdot \frac{2}{2}}}{{{1^3}}} + \frac{{\frac{2}{2}.\frac{3}{2}}}{{{1^3} + {2^3}}} + \frac{{\frac{3}{2}.\frac{4}{2}}}{{{1^3} + {2^3} + {3^3}}} + ... upto nn terms is equal to
View answer and explanation
Correct option: B
nn+1\frac{n}{{n + 1}}
Option B (nn+1\frac{n}{{n + 1}}) is correct because the series telescopes to this result after simplification and partial fraction decomposition.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.