$_7{N^{14}}$ is bombarded with $_2{\rm{H}}{{\rm{e}}^4}$. The resulting nucleus is $_8{{\rm{O}}^{17}}$ with the emission of

JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1

_7{N^{14}}

is bombarded with

_2\mathrm{H}{\mathrm{e}^4}

. The resulting nucleus is

_8{\mathrm{O}^{17}}

with the emission of

View answer and explanation

Correct option: C

Proton

Option C (Proton) is correct because the nuclear reaction equation balances with the emission of a proton.

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\mathrm{7}

\mathrm{2}\,\,\mathrm{fermi}

\mathrm{189}

N{e^{22}}

\alpha -