JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

Statement I: The distance covered by a body is given by

s=u+\frac{1}{2} \frac{a}{t}

, where the symbols have usual meaning.

Statement II: We can add, substract or equate quantities which have same dimensions.

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Correct option: D

Statement I is false; Statement II is true

Option D is correct because Statement I is false, and Statement II is true. The given equation for distance is dimensionally incorrect, while it is true that quantities with the same dimensions can be added, subtracted, or equated.

More Questions from UNITS & MEASUREMENTS

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Assertion :

\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

has the unit

\mathrm{ms}^{-1} \text {. }

Reason: Acceleration has the dimensions of

\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

The method of dimensional analysis can be used to derive which of the following relations? Statement-I: Dimensions of constant of proportionality of constants can be derived from dimensional method
Statement-II: Numerical value of constant of proportionality can be found from experiments only The dimensions of torque are The physical quantity having the dimensions

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

is A quantity X is given by

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

, where

{\varepsilon _0}

is the permittivity of free space, L is a length,

{\Delta V}

is a potential difference and

{\Delta t}

is a time interval. The dimensional formula for X is the same as that of