At two points $P\;and\;Q$ on screen in Young's double slit experiment. Waves from slits ${S_1}\;and\;{S_2}$ have a path difference of $0\;{\rm{and}}\;\frac{\lambda }{4}{\rm{.}}$ respectively. The ratio of intensities at $P\;and\;Q$ will be

JEE PHYSICS MCQ: WAVE OPTICS

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At two points

P\;and\;Q

on screen in Young's double slit experiment. Waves from slits

{S_1}\;and\;{S_2}

have a path difference of

0\;\mathrm{and}\;\frac{\lambda }{4}\mathrm{.}

respectively. The ratio of intensities at

P\;and\;Q

will be

View answer and explanation

Correct option: B

2:1

Option B (2:1) is correct because the ratio of intensities is calculated using the path difference and the formula for intensity in interference.

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10^{-3}

500 {~nm}

0.01\;SI

200\;kg{m^{ - 3}}

0.25\;m

0.4\;rad