JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

The energy of the electron in the second and the third Bohr's orbits of the hydrogen atom is

-5.42 \times 10^{-12}

erg and

-2.41 \times 10^{-12}

erg respectively. Calculate the wavelength of the emitted radiation when the electron drops from the third to the second orbit.

View answer and explanation

Correct option: A

6.6 \times 10^3 \mathop {\text{A}}\limits^ \circ

Option A (

6.6 \times 10^3 \mathop{\text{A}}\limits^\circ

) is correct because it is the calculated wavelength of the emitted radiation when the electron transitions from the third to the second Bohr orbit.

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