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JEE PHYSICS MCQ: RAY OPTICS

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A ray of light enters a rectangular glass slab of refractive index 3\sqrt{3} at angle of incidence 60∘60^{\circ}. It ravels a distance of 10 cm10 \mathrm{~cm} inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays is
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Correct option: D
5 cm5 \mathrm{~cm}
Option D (5 cm5 \text{ cm}) is correct because it's calculated using the formula for lateral shift, considering the angle of incidence, angle of refraction, and thickness of the slab.

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