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JEE MATHEMATICS MCQ: ELLIPSE

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Analyzing +4 | -1
Three points A,B,CA,B,C are taken on the ellipse x2a2+y2b2=1\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1 with eccentric angles θ,θ+α and θ+2α\mathrm{\theta },\mathrm{\theta } + \mathrm{\alpha }\,\mathrm{and }\,\mathrm{\theta } + 2\mathrm{\alpha }, then
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Correct option: D
The maximum value of area is 334ab\frac{{3\sqrt 3 }}{4}ab
Option D (The maximum value of area is 334ab\frac{{3\sqrt 3 }}{4}ab) is correct because the area of the triangle formed by the points on the ellipse is maximized when cos⁡α=−12\cos \alpha = -\frac{1}{2}, resulting in the maximum area of 334ab\frac{{3\sqrt 3 }}{4}ab.

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